Groomsmen Gift

Groomsmen's Best Man Gifts from Excalibur Groomsmen and Best Man gifts are the hardest gifts to find and usually the last item checked off your wedding to-do list. We specialize in groomsmen's gifts and have selected a few of our most popular your groomsmen will always cherish. Excalibur offers secure online ordering, guaranteed return policy, gift wrapping and prompt, FREE SHIPPING . Groomsmen's Gifts are shown on the following pages or go directly to an item by clicking on the photo below. Leather 6 oz. flask , $19.95 Golf Divot Key Ring, $14.95 Twin Nail Set , $39.95 Engravable Beer Stein, $29.95 Byrd Knife by Spyderco, $27.95 Liquor Flask 7 oz. Stainless, $29.95 Kershaw Money Clip, $46.95 Silver Business Card Holder, $19.95 Leatherman Micra Tool, SPECIAL $26.95 MACH III Razor and Stand, $24.95 Banded liquor flask, $34.95 Best Man Stein, $57.50 Gentlemen's Finger Nail Clipper, $27.95 Zippo Lighter, $14.95 Gentlemen's Pocket Knife, $26.95 Stainless Money Clip, $14.95 Cigar Cutter, $24.95 Gerber Silver Knight pocket knife, $66.95 Buck Gentlemen's Knife, 26.95 Columbia River Knife & Tool, Delilah's PECK, $29.95 Swiss Army, The Classic , $16.95 Swiss Army Alox Classic, $24.95 X750 Fisher Space Pen. $29.95 Pewter Shot Glasses from $17.95 Al Mar Cash Clip, $36.95 Double Walled Tankard, $29.95 Money clip credit card holder, $24.95 Money clip pocket watch, $29.95 Mach III Shaving Set, $59.95 Championship Poker Set, $79.95 Deluxe Leather Flask, engravable, $39.95 Surefire G-2 Nitrolon Flashlight, $39.95 Groomsmen's gift suggestions continued on following pages. Wedding Gift Suggestions Men's Gifts Sports and Pocket Knives Multi-tools Flasks Medieval and Samurai Swords and Medieval Collectibles ©2005 Excalibur All rights reserved. All other trademarks belong to their respective owners. If you have any concerns or problems with our site, please contact the Webmaster, AdSense Consulting .

Birthday Present

Math Forum: Ask Dr. Math FAQ: The Birthday Problem -- Ask Dr. Math: FAQ The Birthday Problem Dr. Math FAQ || Classic Problems || Formulas || Search Dr. Math || Dr. Math Home Suppose you flip a coin and bet that it will come up tails. Since you are equally likely to get heads or tails, the probability of tails is 50%. This means that if you try this bet often, you should win about half the time. What if somebody offered to bet that at least two people in your math class had the same birthday? Would you take the bet? This question is more complicated than flipping a coin, because the chance of finding two people with the same birthday depends on the number of people you ask. If there were only one other person in your math class, you might be surprised to find out that she had the same birthday as you. If there were a pair of people with the same birthday in a class of 366 people, would you still be surprised? How large must a class be to make the probability of finding two people with the same birthday at least 50%? Let's forget about leap year when we solve this problem (no February 29 birthdays!) This way, we can assume that a year is always 365 days long. We'll start by figuring out the probability that two people have the same birthday. The first person can have any birthday. That gives him 365 possible birthdays out of 365 days, so the probability of the first person having the "right" birthday is 365/365, or 100%. The chance that the second person has the same birthday is 1/365. To find the probability that both people have this birthday, we have to multiply their separate probabilities. (365/365) * (1/365) = 1/365, or about 0.27%. Now, what about three people ? The chance of the first and second person sharing a birthday is still 1/365. The first and third person might share a birthday instead. The probability of that is 1/365 as well. But what if the second and third person shared a birthday? And what if all three of them had the same birthday? Things are getting complicated fast. Four or five people would be even messier. Is there a simpler way? To solve the birthday problem, we need to use one of the basic rules of probability: the sum of the probability that an event will happen and the probability that the event won't happen is always 1. (In other words, the chance that anything might or might nothappen is always 100%.) If we can work out the probability that no two people will have the same birthday, we can use this rule to find the probability that two people will share a birthday: P(event happens) + P(event doesn't happen) = 1 P(two people share birthday) + P(no two people share birthday) = 1 P(two people share birthday) = 1 - P(no two people share birthday). So, what is the probability that no two people will share a birthday? Again, the first person can have any birthday. The second person's birthday has to be different. There are 364 different days to choose from, so the chance that two people have different birthdays is 364/365. That leaves 363 birthdays out of 365 open for the third person. To find the probability that both the second person and the third person will have different birthdays, we have to multiply: (365/365) * (364/365) * (363/365) = 132 132/133 225, which is about 99.18%. If we want to know the probability that four people will all have different birthdays, we multiply again: (364/365) * (363/365) * (362/365) = 47 831 784/ 48 627 125, or about 98.36%. We can keep on going the same way as long as we want. A formula for the probability that n people have different birthdays is ((365-1)/365) * ((365-2)/365) * ((365-3)/365) * . . . * ((365-n+1)/365). If you know permutation notation, you can write this formula as (365_P_n)/(365^n). That's the same as 365! / ((365-n)! * 365^n). We've made some progress, but we still haven't answered the original question: how large must a class be to make the probability of finding two people with the same birthday at least 50%? We know that the probability of finding at least two people with the same birthday is 1 minus the probability that everybody has a different birthday, and we know how to find the probability that everybody has a different birthday for any number of people. The easiest way to find the right class size is to use a calculator to try different numbers in the formula. It turns out that the smallest class where the chance of finding two people with the same birthday is more than 50% is... a class of 23 people . (The probability is about 50.73%.) From the Dr. Math archives: Probability Theory: Coincidental Birthday Probability of the Same Birthday within a Group Birthday Probabilities Three Share a Birthday The Birthday Problem; Queuing at a Bank Birthday Probability, Class of 25 One Person of Seven Born on Monday Odds of Left-Handedness in a Group From the Web: The Birthday Problem: A short lesson in probability , George Reese A Java applet that you can use to test different class sizes (it works better with small classes) and graphs of the probability for different numbers of people. The Law of Small Errors , Keith Devlin The birthday problem, and related questions - what's the probability that someone will have your birthday? Birthday Surprises, Ivars Peterson Birthday Problem, Eric Weisstein's World of Mathematics Coincidence, Alexander Bogomolny How to Read Mathematics, Shai Simonson and Fernando Gouveau This article uses an explanation of the birthday problem as an example. An Introduction to Mathematica and the "Birthday Problem," Louie Beuschlein For a general review of probability: Probability, Dr. Math FAQ Probability in the Real World, Dr. Math FAQ - Ursula Whitcher, for the Math Forum Submit your ownquestion to Dr. Math [ Privacy Policy ] [ Terms of Use ] Math Forum Home || Math Library || Quick Reference || Math Forum Search Ask Dr. Math ® © 1994-2005 The Math Forum http://mathforum.org/dr.math/

Buy Gift

Saffron Gift Certificates - Indian Restaurant, Morris County, NJ Thursday, September 22, 2005 Quick Facts Open 7 Days A Week Lunch: 11:30 AM - 03:00 PM Dinner: 05:00 PM - 10:00 PM (Until 10:30 PM on weekends) 249 Route 10 East, East Hanover, NJ Ph.#: (973) 599-0700 Fx.#: (973) 599-9444 Across from Dick's Sporting Goods and next to T-Mobile. [more information] Remember to check our online COUPONS and save money on your next order. Be sure to try out our online ordering system . It's easy. Gift Certificates Please complete the form below. Fields marked with * are required Credit Card Billing Information: First Name: * Last Name: * Address: * Address 2: City: * State: Alaska Alabama Arkansas Arizona California Colorado Connecticut District of Colombia Delaware Florida Georgia Hawaii Idaho Illinois Indiana Iowa Kansas Kentucky Louisiana Massachusetts Maryland Maine Michigan Minnesota Missouri Mississippi Montana Nebraska North Carolina New Hampshire New Jersey New Mexico Nevada New York Ohio Oklahoma Oregon Pennsylvania Puerto Rico Rhode Island South Carolina Tennesee Texas Utah Virginia U.S. Virgin Islands Vermont Washington Wisconsin West Virginia Wyoming * Zip: * Phone Number: * Example: (000) 555-1212 E-Mail: Credit Card Information Credit Card: American Express Diner's Club Discover MasterCard Visa * Credit Card Number: * Expiration Date: 1 2 3 4 5 6 7 8 9 10 11 12 / 2005 2006 2007 2008 2009 * Gift Certificate Information Quantity Requested * Amount $50.00 $75.00 $100.00 * Ship To Address ( if different from above ): Name: Address: Address 2: City: State: Zip: Recepient Name (To): Optional Sender Name (From): Optional Shipping Method: Pick Up At Restaurant - $0.00 Regular Mail - $0.00 Comments: Gift Certificates are valid for one (1) year from date of purchase. You shall be charged for the Gift Certificate(s) directly from Saffron Indian Cuisine. You agree to pay for this purchase in accordance with your credit card agreement. This page is powered by D. J. Ardore's restaurantPassion.com And is subject to the Website User Agreement (User Terms of Service) Home About Us Information Picture Tour The Owner Coupons! The Food Lunch & Dinner Catering View Takeout Menu Order Takeout Online! Coupons! Order Takeout Make Reservations

Christmas gift ideas with

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Shower Gift Bingo [TKB2430]

Shower Gift Bingo -- Largest Selection of CLICK HERE Product Search Categories BOOKS & MUSIC Books CDs and Video Planner COLLECTIONS Hortense & Kerenza Beverly Clark CEREMONY Aisle Runners Baskets Candles & Holders Purses & Money Bags Ring Pillows Tussie Mussies FAVORS Boxes & Bags Bubbles & Bells Candy Wrappers/Seals Favor Tags Personalized Favors Sweets Unique Favors GIFTS Accessories Anniversary Bar & Glassware Bridesmaid Gifts Childrens Gifts Groomsmen Gifts Key Chains Parents Gifts Wedding Keepsakes INVITATIONS Carlson Craft Regency JEWELRY Gem & Rhinestone Jewelry Boxes Pearl Jewelry Silver Jewelry Tiaras JUST FOR FUN Bridal Accessories Bridal Shower Games Clothing Novelty Items RECEPTION Albums Cake Serving Sets Cake Tops Cameras Centerpieces Decorations Garters Guest Books Pen Sets Placecard Holders & Frames Toasting Glasses STATIONERY Bookmarks Invitations Marriage Certificates Other Stationery Placecards Programs Thank You Other Useful Links Wedding Stationery Helpful guidelines on how to select your wedding invitation ensemble Login | Order Tracking | View Cart SHOWING PRODUCT FROMS FROM: WEDDING SOLUTIONS JUST FOR FUN » Bridal Shower Games Shower Gift Bingo [TKB2430] $31.50 Click to enlarge Break the ice and get shower guests involved with this bridal edition of the classic bingo game. The rules are simple: As the bride opens her gifts, one bridesmaid serves as the "caller" while the other guests mark their pre-printed bingo cards with corresponding names of possible gift items such as "Bakeware," "Coffee Grinder," "Bath Accessories," or "Lingerie." The first person to get five in a row and yell "Bingo" wins! Set includes 50 unique bingo cards, 1 caller card, and instructions. White-and-red cards measure 5 1/4" w x 6 3/4" h each. Policies | Contact Us | View Cart | FAQ's | Home Wedding Accessories | Wedding Favors --