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Gift Baskets: Corporate,New Baby,Holiday,Birthday Gift Baskets - Gourmet Gift Basket Gift Categories Home Page All Baskets Chocolates Corporate Gourmet Occasions Romantic Baby Gifts Birthday Get Well New Home Sympathy Thank You Wedding Gifts Holidays Christmas Valentine's Easter Mother's Day Father's Day Fourth of July Specialties Patriotic Sweets Coffee & Tea Garden Gifts For Her Gifts For Him Gifts For Kids Low Carb Catalog Favorite Links Fancy Gift Baskets Gift Baskets for all occasions is our specialty. Whether you are searching for Corporate Gift Baskets, Holiday Gift Baskets, New Baby Gift Baskets, Wedding gifts, Gourmet, Food or Birthday Gift Baskets, we would like to be your first choice for unique gifts. Baskets By Occasion Baskets By Holiday Baskets By Specialty View All Gift Baskets Gourmet Gift Baskets Corporate Gift Baskets Whether you're selecting a gift to celebrate, to motivate or congratulate... to show affection, appreciation, recognition... to express your joy, caring or esteem... you want the recipient to know you took personal care to make sure their gift is very special. And so do we. This is why we dedicate our efforts to producing specialty gift arrangements that combine originality, style and most of all quality. Our unique Baskets are filled with food , crackers, cookies, chocolates, coffee, tea, nuts, cheeses, and much more. You can find a gift for any occasion, any holiday , or for that special person in your life. If you are looking for a Gourmet, Thank You, Birthday, Christmas , Valentine's, Wedding, Father's Day, Mother's Day, or New Baby Gift Baskets. You would love our collection. Our collection of gift arrangements captures the latest trends in style and ingredient selection, so your gift will be unforgettable and in perfect taste. Our commitment to quality and value is your assurance the recipient will be delighted, whatever the occasion. We offer three shipping methods : UPS Ground, Airborne Express 2-Day Air, & Airborne Express Overnight Air. Saturdays and Sundays are not counted when calculating the number of days a parcel will spend in transit. All orders received after 12noon EST /9AM PST will go out the following business day (Mon-Fri). We deliver our gift baskets to the following States: Alabama, Alaska, Arizona, Arkansas, California, Colorado, Connecticut, Delaware, Florida, Georgia, Hawaii, Idaho, Illinois, Indiana, Iowa, Kansas, Kentucky, Louisiana, Maine, Maryland, Massachusetts, Michigan, Minnesota, Mississippi, Missouri, Montana, Nebraska, Nevada, Mew Hampshire, New Jersey, New Mexico, New York, North Carolina, North Dakota, Ohio, Oklahoma, Oregon, Pennsylvania, Rhode Island, South Carolina, South Dakota, Tennessee, Texas, Utah, Vermont, Virginia, Washington, Washington D.C., West Virginia, Wisconsin, Wyoming. To see specific types of gifts, please click the links below. home all baskets chocolate gift baskets corporate gift baskets gourmet gift baskets romantic gift baskets baby gift baskets birthday gift baskets get well gift baskets new home gifts sympathy gift baskets thank you gift baskets wedding gifts holiday gift baskets christmas gift baskets new baby gifts valentine's gift baskets mother's day gifts father's day gifts cookie gift baskets gifts for her gifts for him gifts for kids coffee and tea gift baskets food gift baskets This site offers secure digital encryption. 2003 FancyGiftBaskets.com, All Rights Reserved. Fancy Gift Baskets Site Map
creative gift giver" (New
Amazon.com: Profile for R. Gonzalez Your Store See All 31 Product Categories   Your Account | Cart | Wish List | Help Improve Your Recommendations | Your Amazon Home | Your Profile | Learn More Search Amazon.com People Web Search Hello. Click here to sign in. New customer? Start here . Invite as Amazon Friend Add to Favorite People E-mail this page R. Gonzalez "creative gift giver" (New York, NY) Need help? More information on Profile Pages Nickname: ricardorgonzalez Reviewer Rank: 1,036,120 – See 1 review (1 helpful vote) Reviews Make-Your-Own Opoly 1 of 1 people found the following review helpful: = Durability = Fun = Educational = Overall AS GREAT AS YOU MAKE IT , August 2, 2005 This is a very easy to use kit, but the game is only as good as you make it. We used it to celebrate the birthday of a favorite uncle and included... Read More Favorite People (2) More to Explore Listmania Lists | So You'd Like To... Guides | Shared Purchases Where's My Stuff? Track your recent orders . View or change your orders in Your Account . Shipping & Returns See our shipping rates & policies . Return an item (here's our Returns Policy ). Need Help? Forgot your password? Click here . Redeem or buy a gift certificate. Visit our Help department . Search Amazon.com Books Popular Music Music Downloads Classical Music DVD VHS Apparel Yellow Pages Restaurants Movie Showtimes Toys Baby Computers Video Games Electronics Camera & Photo Software Tools & Hardware Office Products Magazines Sports & Outdoors Outdoor Living Kitchen Jewelry & Watches Beauty Gourmet Food Beta Musical Instruments Health/Personal Care Pet Supplies Travel Cell Phones & Service Outlet Auctions zShops Everything Else Scientific Supplies Medical Supplies Indust. Supplies Automotive Home Furnishings Lifestyle Arts & Hobbies for Amazon.com Home | Directory of All Stores Our International Sites: Canada | United Kingdom | Germany | Japan | France | China Contact Us | Help | Shopping Cart | Your Account | Sell Items | 1-Click Settings Investor Relations | Press Releases | Careers Conditions of Use | Privacy Notice © 1996-2005, Amazon.com, Inc. or its affiliates
Birthday Present
Math Forum: Ask Dr. Math FAQ: The Birthday Problem -- Ask Dr. Math: FAQ The Birthday Problem Dr. Math FAQ || Classic Problems || Formulas || Search Dr. Math || Dr. Math Home Suppose you flip a coin and bet that it will come up tails. Since you are equally likely to get heads or tails, the probability of tails is 50%. This means that if you try this bet often, you should win about half the time. What if somebody offered to bet that at least two people in your math class had the same birthday? Would you take the bet? This question is more complicated than flipping a coin, because the chance of finding two people with the same birthday depends on the number of people you ask. If there were only one other person in your math class, you might be surprised to find out that she had the same birthday as you. If there were a pair of people with the same birthday in a class of 366 people, would you still be surprised? How large must a class be to make the probability of finding two people with the same birthday at least 50%? Let's forget about leap year when we solve this problem (no February 29 birthdays!) This way, we can assume that a year is always 365 days long. We'll start by figuring out the probability that two people have the same birthday. The first person can have any birthday. That gives him 365 possible birthdays out of 365 days, so the probability of the first person having the "right" birthday is 365/365, or 100%. The chance that the second person has the same birthday is 1/365. To find the probability that both people have this birthday, we have to multiply their separate probabilities. (365/365) * (1/365) = 1/365, or about 0.27%. Now, what about three people ? The chance of the first and second person sharing a birthday is still 1/365. The first and third person might share a birthday instead. The probability of that is 1/365 as well. But what if the second and third person shared a birthday? And what if all three of them had the same birthday? Things are getting complicated fast. Four or five people would be even messier. Is there a simpler way? To solve the birthday problem, we need to use one of the basic rules of probability: the sum of the probability that an event will happen and the probability that the event won't happen is always 1. (In other words, the chance that anything might or might nothappen is always 100%.) If we can work out the probability that no two people will have the same birthday, we can use this rule to find the probability that two people will share a birthday: P(event happens) + P(event doesn't happen) = 1 P(two people share birthday) + P(no two people share birthday) = 1 P(two people share birthday) = 1 - P(no two people share birthday). So, what is the probability that no two people will share a birthday? Again, the first person can have any birthday. The second person's birthday has to be different. There are 364 different days to choose from, so the chance that two people have different birthdays is 364/365. That leaves 363 birthdays out of 365 open for the third person. To find the probability that both the second person and the third person will have different birthdays, we have to multiply: (365/365) * (364/365) * (363/365) = 132 132/133 225, which is about 99.18%. If we want to know the probability that four people will all have different birthdays, we multiply again: (364/365) * (363/365) * (362/365) = 47 831 784/ 48 627 125, or about 98.36%. We can keep on going the same way as long as we want. A formula for the probability that n people have different birthdays is ((365-1)/365) * ((365-2)/365) * ((365-3)/365) * . . . * ((365-n+1)/365). If you know permutation notation, you can write this formula as (365_P_n)/(365^n). That's the same as 365! / ((365-n)! * 365^n). We've made some progress, but we still haven't answered the original question: how large must a class be to make the probability of finding two people with the same birthday at least 50%? We know that the probability of finding at least two people with the same birthday is 1 minus the probability that everybody has a different birthday, and we know how to find the probability that everybody has a different birthday for any number of people. The easiest way to find the right class size is to use a calculator to try different numbers in the formula. It turns out that the smallest class where the chance of finding two people with the same birthday is more than 50% is... a class of 23 people . (The probability is about 50.73%.) From the Dr. Math archives: Probability Theory: Coincidental Birthday Probability of the Same Birthday within a Group Birthday Probabilities Three Share a Birthday The Birthday Problem; Queuing at a Bank Birthday Probability, Class of 25 One Person of Seven Born on Monday Odds of Left-Handedness in a Group From the Web: The Birthday Problem: A short lesson in probability , George Reese A Java applet that you can use to test different class sizes (it works better with small classes) and graphs of the probability for different numbers of people. The Law of Small Errors , Keith Devlin The birthday problem, and related questions - what's the probability that someone will have your birthday? Birthday Surprises, Ivars Peterson Birthday Problem, Eric Weisstein's World of Mathematics Coincidence, Alexander Bogomolny How to Read Mathematics, Shai Simonson and Fernando Gouveau This article uses an explanation of the birthday problem as an example. An Introduction to Mathematica and the "Birthday Problem," Louie Beuschlein For a general review of probability: Probability, Dr. Math FAQ Probability in the Real World, Dr. Math FAQ - Ursula Whitcher, for the Math Forum Submit your ownquestion to Dr. Math [ Privacy Policy ] [ Terms of Use ] Math Forum Home || Math Library || Quick Reference || Math Forum Search Ask Dr. Math ® © 1994-2005 The Math Forum http://mathforum.org/dr.math/
Housewarming Gifts - Unique
Housewarming Gift - Unique Housewarming Gifts & Housewarming Gift Ideas Home My Account Sign Up for Email Cart Housewarming Home Gifts Gifts By Occasion Housewarming Page: 1 2 View All Lemongrass Cleaning Collection Shore Cleaning Collection Sweet Orange Cleaning Collection Hillstead Point Frames Campaign Frames Gallery Frame Collection Hastings Candleholders & Hurricanes Grand White Candleholders Rousseau Pillar Holders Cheese Label Plates Postcard Plates & Coasters Monogram Drinkware Housewarming Gifts - Unique Housewarming Gift - Housewarming Gift Idea Housewarming Gift - Many thoughtful Housewarming Gifts are available at Restoration Hardware. If you're looking for a Unique Housewarming Gift that will be treasured throughout the years, we have the perfect selection of items for you to choose from. Unique Housewarming Gifts & Housewarming Gift Ideas Home Gifts Gifts By Occasion Housewarming Page: 1 2 View All Gifts Gifts By Price Gifts Under $25 $25 - $50 $50 - $100 Gifts By Recipient Gifts for Her Gifts for Him Gifts for Kids Gifts By Occasion Birthday Wedding Housewarming Personalized Gifts Our Favorite Gifts Gift Certificate RH Card Catalog Request Shop by Catalog Store Locator Customer Service Company Information Gift Registry Corporate Sales Privacy Policy Terms & Conditions Site Map Sign In © 2005. Restoration Hardware, Inc. All Rights Reserved. 1-800-910-9836 Housewarming Gifts - Unique Housewarming Gift - Housewarming Gift Idea Housewarming Gift - Many thoughtful Housewarming Gifts are available at Restoration Hardware. If you're looking for a Unique Housewarming Gift that will be treasured throughout the years, we have the perfect selection of items for you to choose from. Unique Housewarming Gifts & Housewarming Gift Ideas
Birthday Present
Math Forum: Ask Dr. Math FAQ: The Birthday Problem -- Ask Dr. Math: FAQ The Birthday Problem Dr. Math FAQ || Classic Problems || Formulas || Search Dr. Math || Dr. Math Home Suppose you flip a coin and bet that it will come up tails. Since you are equally likely to get heads or tails, the probability of tails is 50%. This means that if you try this bet often, you should win about half the time. What if somebody offered to bet that at least two people in your math class had the same birthday? Would you take the bet? This question is more complicated than flipping a coin, because the chance of finding two people with the same birthday depends on the number of people you ask. If there were only one other person in your math class, you might be surprised to find out that she had the same birthday as you. If there were a pair of people with the same birthday in a class of 366 people, would you still be surprised? How large must a class be to make the probability of finding two people with the same birthday at least 50%? Let's forget about leap year when we solve this problem (no February 29 birthdays!) This way, we can assume that a year is always 365 days long. We'll start by figuring out the probability that two people have the same birthday. The first person can have any birthday. That gives him 365 possible birthdays out of 365 days, so the probability of the first person having the "right" birthday is 365/365, or 100%. The chance that the second person has the same birthday is 1/365. To find the probability that both people have this birthday, we have to multiply their separate probabilities. (365/365) * (1/365) = 1/365, or about 0.27%. Now, what about three people ? The chance of the first and second person sharing a birthday is still 1/365. The first and third person might share a birthday instead. The probability of that is 1/365 as well. But what if the second and third person shared a birthday? And what if all three of them had the same birthday? Things are getting complicated fast. Four or five people would be even messier. Is there a simpler way? To solve the birthday problem, we need to use one of the basic rules of probability: the sum of the probability that an event will happen and the probability that the event won't happen is always 1. (In other words, the chance that anything might or might nothappen is always 100%.) If we can work out the probability that no two people will have the same birthday, we can use this rule to find the probability that two people will share a birthday: P(event happens) + P(event doesn't happen) = 1 P(two people share birthday) + P(no two people share birthday) = 1 P(two people share birthday) = 1 - P(no two people share birthday). So, what is the probability that no two people will share a birthday? Again, the first person can have any birthday. The second person's birthday has to be different. There are 364 different days to choose from, so the chance that two people have different birthdays is 364/365. That leaves 363 birthdays out of 365 open for the third person. To find the probability that both the second person and the third person will have different birthdays, we have to multiply: (365/365) * (364/365) * (363/365) = 132 132/133 225, which is about 99.18%. If we want to know the probability that four people will all have different birthdays, we multiply again: (364/365) * (363/365) * (362/365) = 47 831 784/ 48 627 125, or about 98.36%. We can keep on going the same way as long as we want. A formula for the probability that n people have different birthdays is ((365-1)/365) * ((365-2)/365) * ((365-3)/365) * . . . * ((365-n+1)/365). If you know permutation notation, you can write this formula as (365_P_n)/(365^n). That's the same as 365! / ((365-n)! * 365^n). We've made some progress, but we still haven't answered the original question: how large must a class be to make the probability of finding two people with the same birthday at least 50%? We know that the probability of finding at least two people with the same birthday is 1 minus the probability that everybody has a different birthday, and we know how to find the probability that everybody has a different birthday for any number of people. The easiest way to find the right class size is to use a calculator to try different numbers in the formula. It turns out that the smallest class where the chance of finding two people with the same birthday is more than 50% is... a class of 23 people . (The probability is about 50.73%.) From the Dr. Math archives: Probability Theory: Coincidental Birthday Probability of the Same Birthday within a Group Birthday Probabilities Three Share a Birthday The Birthday Problem; Queuing at a Bank Birthday Probability, Class of 25 One Person of Seven Born on Monday Odds of Left-Handedness in a Group From the Web: The Birthday Problem: A short lesson in probability , George Reese A Java applet that you can use to test different class sizes (it works better with small classes) and graphs of the probability for different numbers of people. The Law of Small Errors , Keith Devlin The birthday problem, and related questions - what's the probability that someone will have your birthday? Birthday Surprises, Ivars Peterson Birthday Problem, Eric Weisstein's World of Mathematics Coincidence, Alexander Bogomolny How to Read Mathematics, Shai Simonson and Fernando Gouveau This article uses an explanation of the birthday problem as an example. An Introduction to Mathematica and the "Birthday Problem," Louie Beuschlein For a general review of probability: Probability, Dr. Math FAQ Probability in the Real World, Dr. Math FAQ - Ursula Whitcher, for the Math Forum Submit your ownquestion to Dr. Math [ Privacy Policy ] [ Terms of Use ] Math Forum Home || Math Library || Quick Reference || Math Forum Search Ask Dr. Math ® © 1994-2005 The Math Forum http://mathforum.org/dr.math/